2D formulation for Electrostatic Problems
From KratosWiki
(Difference between revisions)
(→2D formulation for Triangular Elements) |
(→2D formulation for Triangular Elements) |
||
Line 155: | Line 155: | ||
\frac{\partial N_3}{\partial \beta}=1 | \frac{\partial N_3}{\partial \beta}=1 | ||
</math> | </math> | ||
+ | |||
+ | |||
+ | ::<math> | ||
+ | x = N_1 x_1 + N_2 x_2 + N_3 x_3 = ( 1 - \alpha - \beta) x_1 + \alpha x_2 + \beta x_3 | ||
+ | </math> | ||
+ | |||
+ | |||
+ | ::<math> | ||
+ | y = N_1 y_1 + N_2 y_2 + N_3 y_3 = ( 1 - \alpha - \beta) y_1 + \alpha y_2 + \beta y_3 | ||
+ | </math> | ||
+ | |||
::<math>\mathbf{J^{(e)}} = | ::<math>\mathbf{J^{(e)}} = |
Revision as of 18:06, 12 November 2009
The 2D Electrostatic Poisson's equation given by the governing PDE and its boundary conditions:
can be written as (see the General formulation for Electrostatic Problems):
with (n is the number of nodes of the element):
2D formulation for Triangular Elements
After applying the numerical integration for triangular elements by using the natural coordinates, we obtain:
- x = N1x1 + N2x2 + N3x3 = (1 − α − β)x1 + αx2 + βx3
- y = N1y1 + N2y2 + N3y3 = (1 − α − β)y1 + αy2 + βy3
Stiffness Matrix K(e)